Bash Script for Comparing Two Conf Directories

I have had a small problem of screwing up my jboss the other day. To get it working again I had to copy my co-worker's jboss directories and start using that. Slight problem with that, all the conf files will now be specific to him and not me e.g. my jndi ports, etc. So I had to go through by hand and fix all of the conf files I could find. Luckily I had a backup of my old conf files to check against. In an effort to track down the differences I wrote the following bash script.

My bash is not good, but it seems to do the trick and will compare files in two directories who's only difference is the path.

#!/bin/bash

#List the files that end with 'xml' in the final directory of $1 (you specify $1
#as the first arg on the command line)
#Note that when you list with a wild card *nix will list out the full path. If you know how to disable that #for ls, then you can use that instead, but I didn't see anything in the man pages. Therfore, strip it #out with a quick and dirty regex

ls /home/blah/jboss/server/all/$1/*xml > dir

orig_jboss="/home/blah/jboss-4.2.3.GA.20090611/server/all/$1/"
new_jboss="/home/blah/jboss/server/all/$1/"

#note the >>. If you don't put both it will only write the last one into the new file.
#>> will force an append
for file in `cat dir`; do echo ${file#/home*$1/} >> actual_dir ; done

for i in `cat actual_dir`; do diff $new_jboss$i $orig_jboss$i ; done

#If you don't do this and run the script a few times, you'll keep appending more
#things into 'actual_dir'
rm dir actual_dir

If everything is the same you shouldn't see any output. Otherwise you'll get a list of all the differences without having to do much by hand.